Answer In Deg And Rad - C And C++ | Dream.In.Code

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4 Replies - 65 Views - Last Post: Yesterday, 09:46 PM Rate Topic:

#1 seraz ?

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Posted Yesterday, 08:32 PM

this is my coding...
for this coding my result should be 6 iteration only...
im not very sure whether my answer in rad or deg...
ples someone help me...

 #include<stdio.h> #include<math.h> #include<stdlib.h> #define true 1; #define false 0;  main() { 	int i,m,OK,it; 	double c,d,TOL,fx[100],dfx[100],a[100],x[100]; 	x[0]=2.3,i=0; 	TOL=(pow(10,-32)); 	m=2; 	 	fx[0]=pow((pow(sin(x[0]),2)-pow(x[0],2)+1),2); 	d=fabs(fx[0]); 	printf("%d	%.12e	%.12e\n",i,x[0],d); 	 	OK=false; 	it=0; 	i=0; 	while(!OK) 	{ 		 		it=it+1; 		fx[i]=pow((pow(sin(x[i]),2)-pow(x[i],2)+1),2); 		dfx[i]=2*(pow(sin(x[i]),2)-pow(x[i],2)+1)*(2*sin(x[i])*cos(x[i])-2*x[i]); 	 		x[i+1]=x[i]-(m*(fx[i]/dfx[i])); 		fx[i+1]=pow((pow(sin(x[i+1]),2)-pow(x[i+1],2)+1),2); 	 		c=fabs(fx[i+1]); 		printf("%d	%.12e	%.12e\n",i+1,x[i+1],c); 		 	if(c<TOL) OK=true;  i=i+1;  	} } 

This post has been edited by Skydiver: Yesterday, 08:42 PM

Is This A Good Question/Topic? 0

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Replies To: answer in deg and rad

#2 Skydiver ?

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Re: answer in deg and rad

Posted Yesterday, 08:54 PM

Try increasing your tolerance to 10^-30 instead of 10^-32.

This post has been edited by Skydiver: Yesterday, 08:55 PM

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#3 seraz ?

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Re: answer in deg and rad

Posted Yesterday, 09:25 PM

Skydiver, on 07 April 2013 - 08:54 PM, said:

Try increasing your tolerance to 10^-30 instead of 10^-32.

i cannot do that...
because it already fit in my project...
i want to observe the number of iteration with same TOL but different test function

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#4 Skydiver ?

Reputation: 1739

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Re: answer in deg and rad

Posted Yesterday, 09:38 PM

Well, base on the values of C, I don't see how you will ever get a value of c less than 10^-32 in 6 iterations.

Here's the output I'm seeing:

 0       2.300000000000e+000     1.394218647024e+001 1       1.632475867168e+000     4.472626765749e-001 2       1.435079952458e+000     6.046710267708e-003 3       1.405195569536e+000     3.057005611515e-006 4       1.404492036112e+000     9.272594171137e-013 5       1.404491648215e+000     8.590695257857e-026 6       1.404491648215e+000     1.109335647967e-031 7       1.404491648215e+000     1.972152263053e-031 8       1.404491648215e+000     1.109335647967e-031 9       1.404491648215e+000     1.972152263053e-031 10      1.404491648215e+000     1.109335647967e-031 11      1.404491648215e+000     1.972152263053e-031 12      1.404491648215e+000     1.109335647967e-031 13      1.404491648215e+000     1.972152263053e-031 : until it overruns the buffers you declared. 

How did you determine that 6 iterations was going to be sufficient?

This post has been edited by Skydiver: Yesterday, 09:43 PM

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#5 Skydiver ?

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Re: answer in deg and rad

Posted Yesterday, 09:46 PM

Perhaps use GMP or MPIR as your number and math library instead of the standard C/C++ library to get more precision and perhaps get past the repetition that is happening above.

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